| Thread | Last Post | Replies |
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| Networking Access 2003 across different sites | 22 May 2008 20:40 GMT | 1 |
Ihave built many networked datases and have always used the technique of splitting the data tables placing them on a mapped drive and providing each user with a frontend that links to the data tables. However we have a client that has a client/server network installed on one
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| Using DSum To Display Running Total On Form | 22 May 2008 20:35 GMT | 7 |
I have a form that tracks vacation hours accrued and taken. The Fields are as follows: Week Period End Date Accrued Hours Hours Taken Balance 1 12/26/07 3.08 0.0
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| Multiply a field | 22 May 2008 20:09 GMT | 8 |
I would like to have a field be mulitplied by a set number and that number be stored in another field, for example: We copy medical records and charge a .75 cents per page. What I would like to do is that when the number of copies is entered into field it will be
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| Primary Keys, Indexes, Relations (inability to update/edit queries | 22 May 2008 19:59 GMT | 5 |
Created an employee database with the following tables: Employee Info Haz Mat Training Records Safety Training Records
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| Query -Change Column Headings each time | 22 May 2008 19:48 GMT | 2 |
I am a new user of Access. I am not sure this is a right question. Assume I have two tabels Jan Feb Mar Apr May Jun Table 1 Budget 98 98 56 45 879 99
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| Choose function does not appear to be rounding the index | 22 May 2008 19:27 GMT | 2 |
I have a text field in a report named NumberRating and I want it to provide the average rating of all the records displayed. If I use the command =Avg([NumberRating]) in the Control Source and set the Format = Fixed and Decimal Places = 0, I get the appropriate results. For ...
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| Database placed in a state by user . . prevents it from being open | 22 May 2008 19:22 GMT | 6 |
I have observed this problem on three different machines, with three different applications. I have come to the conclusion that it must be something about the computer itself. The problem is not related to the number of users. I have one user who opens that database and if ...
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| Validation help | 22 May 2008 19:21 GMT | 1 |
this for my own practice, not for profit. I have run into this situation a couple times and never known hot to go about it OK, I have 3 fields: date, time start and duration (or could be time end) How can do I go about making it so that these fields can't overlap or have
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| #Delete | 22 May 2008 17:51 GMT | 2 |
I have been getting “#Delete” in every field between ID 1541 and 1542 in my Table. I can delete the line by selecting the deleting it, and ACCESS even asks me if I'm sure I want to delete it. The problem is this; It deletes’, but when I close the table it comes back (same line) ...
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| Some answers 2 [TIC] | 22 May 2008 17:19 GMT | 1 |
Sorry I've been away so long, people, but I've been immersed in Web 2.0. These newsgroup posts take too long to open and read, so here's some quick-fire answers based on the titles alone: Q. Very basic ADO VB code on a Form
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| Unbound text box returns nothing | 22 May 2008 16:31 GMT | 1 |
I have an unbound text box, on a subform, which is located on a tab. I have been unable to make the source of this text box return any data. I have tried DLookup from a query: =Dlookup("AOH","[Amt Query]","productID="& Me.productID)
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| reduce Access 2007 database size | 22 May 2008 16:26 GMT | 6 |
I am taking over an old application in Access 2003 which has reached 2GB in size. When the user tried to compress the database, he got an error message. I converted the database to Access 2007 and now the size shows 2,096,160KB.
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| Urgent - Create column on query depending on another column text | 22 May 2008 16:20 GMT | 1 |
HI.. i need help on solving one big problem i can't get the solution.. I have a query that gets some values and also a month text from one table.. based on a form parameters.. What i want to do is to add/create a column on the query and make that column depend on the text of ...
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| Expression | 22 May 2008 16:18 GMT | 2 |
I have a column named Admin in a query, it's values are either "0", ".5" or values > .5 In the expression I would like to return the "0" as "0", and if the value is
> .5 I would like .5 subtracted from the >.5 value. |
| Testing email | 22 May 2008 16:13 GMT | 1 |
Hi hayley barker can u send an email ?
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