John wrote in message <#Gy9zpJJGHA.1832@TK2MSFTNGP11.phx.gbl> :
> Hi
>
[quoted text clipped - 4 lines]
>
> Regards
I think the String function exists a97. Say you have a variable strTest
containint "hello"
strNewWar = strTest & String(20 - len(strTest), "@")
I think also the LSet statement could be used
strNewWar = "12345678901234567890"
LSet strNewWar = strTest

Signature
Roy-Vidar
strOut = Left$(strIn & Space$(x), x)
MS Access - A legend in it's own time.