I already told you how to convert that string into a proper date/time two
days ago, Scott:
CDate(Replace(Replace([id], "T", " "), "Z", "")))
That means use
NewDate: DateValue(DateAdd("h",-6,CDate(Replace(Replace([StartTime], "T",
" "), "Z", "")))))
NewTime: Format(DateAdd("h",-6,CDate(Replace(Replace([StartTime], "T", "
"), "Z", "")))), "Medium Time")

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Doug Steele, Microsoft Access MVP
http://I.Am/DougSteele
(no e-mails, please!)
> Did you create the data fields and get test the solution? The solution
> returned an error in my database. I think it is because the STARTTIME
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>> > Thank you,
>> > Scott
Scott - 30 May 2008 19:29 GMT
You are awesome! Thank you. You're right, you gave me the solution for the
conversion two days ago but I still needed to back up the GMT to local time
and when I tried to do that using the DateAdd function I would get data like
"12/29/1899 8:00:44 PM" (the year 1899?) if it crossed back into the previous
day. Obviously, I wasn't doing something right.
Thanks for your help and yes you did answer both my questions correctly; I'm
set!
Scott
> I already told you how to convert that string into a proper date/time two
> days ago, Scott:
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> >> > Thank you,
> >> > Scott
Douglas J. Steele - 30 May 2008 20:14 GMT
Were you trying to use DateAdd on just the time?
Access really doesn't support time-only. The Date/Time data type is an eight
byte floating point number where the integer portion represents the date as
the number of days relative to 30 Dec, 1899, and the decimal portion
represents the time as a fraction of a day. When you store only a time,
Access leave the integer portion as 0, which means that particular time on
30 Dec, 1899. Doing arithmetic on the time, therefore, can lead to a
different time on a different day. That's also the reason why you cannot add
times together in Access: once the total exceeds 24 hours (1.0), you get a
time on a different day.

Signature
Doug Steele, Microsoft Access MVP
http://I.Am/DougSteele
(no e-mails, please!)
> You are awesome! Thank you. You're right, you gave me the solution for
> the
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>> >> > Thank you,
>> >> > Scott
Scott - 30 May 2008 20:27 GMT
That's what I was doing. Thanks again for your help!
> Were you trying to use DateAdd on just the time?
>
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> >> >> > Thank you,
> >> >> > Scott