Thanks for your reply Mr. Browne,
I am still confused, I tried typing =IIf(isError( )Trim([CLFirst] & " " &
[CLInitial] & " " & [CLLast]) and a couple of different ways but I get an
alert that I am not doing something right and resets the formula back to
where it was.
Could you shed some more light on this?
Thanks
Dax
You do not have anything inside the IsError() brackets for it to test:
Try something like this:
=IIf(IsError([CLFirst] & " " & [CLInitial] & " " & [CLLast]), Null,
Trim([CLFirst] & " " & [CLInitial] & " " & [CLLast]))

Signature
Allen Browne - Microsoft MVP. Perth, Western Australia.
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Reply to group, rather than allenbrowne at mvps dot org.
> Thanks for your reply Mr. Browne,
> I am still confused, I tried typing =IIf(isError( )Trim([CLFirst] & " " &
[quoted text clipped - 19 lines]
>> >
>> > I would like to get rid of the # Error but I don't know how.
Memphis - 02 Dec 2005 19:56 GMT
It took a while to figure this out but after reading your reply and some
other replies here I was able to piece this together and it works out:
=IIf([HasData],Trim([CLFirst] & " " & [CLInitial] & " " & [CLLast]),Null)
Thank you for your replies
Dax
> You do not have anything inside the IsError() brackets for it to test:
>
[quoted text clipped - 25 lines]
> >> >
> >> > I would like to get rid of the # Error but I don't know how.
Allen Browne - 03 Dec 2005 02:53 GMT
Yes, testing the HasData property of the report would also be a good
solution.
Great.

Signature
Allen Browne - Microsoft MVP. Perth, Western Australia.
Tips for Access users - http://allenbrowne.com/tips.html
Reply to group, rather than allenbrowne at mvps dot org.
> It took a while to figure this out but after reading your reply and some
> other replies here I was able to piece this together and it works out:
> =IIf([HasData],Trim([CLFirst] & " " & [CLInitial] & " " &
> [CLLast]),Null)