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MS Access Forum / Queries / May 2008

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#Error

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SJW_OST - 29 May 2008 19:43 GMT
I am using the following formula in my Query.

Correct: Left$([List Name],InStrRev([List Name],"_")-1)

I am using this formula to convert some data to the following;

"aaaa_hi_e_28"      converts to   "aaaa_hi_e" or
"aaaa_e_28"          converts to   "aaaa_e"     or
"aaaa_hi_e_0528"  converts to   "aaaa_hi_e"

But, if I have some data that does not have an underscore & "date" at the
end, like D86547, I get #Error. How do I change the formula to just use the
original name if #Error occurs?

Thank you in advance.
Michel Walsh - 29 May 2008 19:50 GMT
prepend one, InStrRev( "_"  & [List Name] ,  "_")  so there will be always
one.

Alternatively, use iif to test the result of InStrRev, and if it returns 0,
let your iif return 1 instead (or whatever the logic dictates).

Vanderghast, Access MVP

>I am using the following formula in my Query.
>
[quoted text clipped - 12 lines]
>
> Thank you in advance.
KARL DEWEY - 29 May 2008 20:18 GMT
I think you need to go with the IIF method as I do believe that 'prepending'
one will return a zero lenght string.

Correct: IIF(InStrRev([List Name], "_")=0, [List Name], Left$([List Name],
InStrRev([List Name],"_")-1))

Signature

KARL DEWEY
Build a little - Test a little

> prepend one, InStrRev( "_"  & [List Name] ,  "_")  so there will be always
> one.
[quoted text clipped - 20 lines]
> >
> > Thank you in advance.
SJW_OST - 29 May 2008 20:26 GMT
That did it! Thank you Karl Dewey and thank you goes to Michel Walsh and
S.Clark as well. All you guys have been a great help. Thank you ver much!

> I think you need to go with the IIF method as I do believe that 'prepending'
> one will return a zero lenght string.
[quoted text clipped - 26 lines]
> > >
> > > Thank you in advance.
SJW_OST - 29 May 2008 20:20 GMT
Ok, so that eliminated the #Error result, if D86547 is an original name. It
now leaves that result blank. I need for it to pull in the original name
also. So if D86547 is an original name I need the same formula to pull
D86547. So with this one formula;

"aaaa_hi_e_28"      converts to   "aaaa_hi_e"
"D86547"               remains        "D86547"

Thank you for your continued assistance.

> prepend one, InStrRev( "_"  & [List Name] ,  "_")  so there will be always
> one.
[quoted text clipped - 20 lines]
> >
> > Thank you in advance.
S.Clark - 29 May 2008 20:52 GMT
Normally, I would use InStr() to check for the existence of the "_", to know
whether to process.  

e.g. IIF(Instr([field], "_") >0, do this, do that)

But, given that you have other underscores in the name, you're going to need
to soul search to determine when a name really has a suffix that you want to
strip.  By soul search, I mean you're going to have to come up with SOME KIND
of naming convention such that programming can occur.

My suggestions would be either:

1. that a suffix is defined as the underscore with four trailing characters.
e.g. _0001, _0ab3, _1234

2. A name can't have any previous underscores

3. a suffix always contains two underscores
e.g. __0001, __a3, __34

Signature

Steve Clark,
Former Access MVP
FMS, Inc
http://www.fmsinc.com/consulting

> Ok, so that eliminated the #Error result, if D86547 is an original name. It
> now leaves that result blank. I need for it to pull in the original name
[quoted text clipped - 30 lines]
> > >
> > > Thank you in advance.
 
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