The Nz function will replace Null to Zero
Nz([FieldName],0)
That might not be the case, but from your post I can't see which tables
involved or what is the join between them.
If you need more help, please post the SQL.

Signature
Good Luck
BS"D
> Hi,
>
[quoted text clipped - 4 lines]
> Thanks,
> Shirley
Thanks for the response, but it's not working. Here is the SQL:
SELECT [PO Query].Project, [PO Query].[PO No], [PO Query].[PO Date], [PO
Query].[Vendor Name], [PO Query].[Sum(amount)], [AP Query].[Sum Of Amount]
FROM [PO Query] LEFT JOIN [AP Query] ON [PO Query].[PO No] = [AP Query].[PO
No]
GROUP BY [PO Query].Project, [PO Query].[PO No], [PO Query].[PO Date], [PO
Query].[Vendor Name], [PO Query].[Sum(amount)], [AP Query].[Sum Of Amount];
Can you still help?

Signature
Shirley
> Hi,
>
[quoted text clipped - 4 lines]
> Thanks,
> Shirley
Ofer Cohen - 08 Nov 2007 21:56 GMT
Have you tried
SELECT [PO Query].Project, [PO Query].[PO No], [PO Query].[PO Date], [PO
Query].[Vendor Name], nz([PO Query].[Sum(amount)],0), Nz([AP Query].[Sum Of
Amount],0)
FROM [PO Query] LEFT JOIN [AP Query] ON [PO Query].[PO No] = [AP Query].[PO
No]
GROUP BY [PO Query].Project, [PO Query].[PO No], [PO Query].[PO Date], [PO
Query].[Vendor Name], [PO Query].[Sum(amount)], [AP Query].[Sum Of Amount];

Signature
Good Luck
BS"D
> Thanks for the response, but it's not working. Here is the SQL:
>
[quoted text clipped - 15 lines]
> > Thanks,
> > Shirley