Dim StrControlNum As String
StrControlNum = Me.yourlistboxname.Column(0) 'assuming you have a unique
identifier for each record
DoCmd.OpenForm "frmData_Entry", acNormal, , "YourUniqueIdentifiedHere= "
& StrControlNum, acFormEdit
you can put this on the double click event if you wish...
Lee-Anne
>Hello all
>
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>
>Does this sound like it is going to work???
Sam - 08 Aug 2005 06:57 GMT
Lee-Anne
Sorry.. you have totally lost me here with the unique identifier. Would the
unique Identifier be the application ID as per my posting or another
identifier???!!!
> Dim StrControlNum As String
> StrControlNum = Me.yourlistboxname.Column(0) 'assuming you have a unique
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> >
> >Does this sound like it is going to work???
Lee-Anne W - 10 Aug 2005 06:08 GMT
hi,
the unique identifier would be the auto number or somethng similiar that is
unique to each record
>Lee-Anne
>
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>> >
>> >Does this sound like it is going to work???
Sam - 10 Aug 2005 08:41 GMT
Thanks Lee-Ann It is working now!
How can I make the list appear in Alphabetical order. The list box captures
Lender, Application ID & Customer name (Customer name is in one box First
name first, last name last) Is there a way of going this????
Thanks
> hi,
>
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> >> >
> >> >Does this sound like it is going to work???
Lee-Anne Waters - 17 Aug 2005 07:40 GMT
hi,
open the list box in design view and open the select query. you can then set
your records to sort ascending or descending on the required fields
Lee-Anne
>Thanks Lee-Ann It is working now!
>
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>> >> >
>> >> >Does this sound like it is going to work???