yes,
the button as is now probably has something like this
DoCmd.Close acForm, "FormName"
change it to
Private Sub cmdExit_Click()
   If MsgBox("This action will close Access. Do you still
wish to continue?", vbYesNo, "Exit Application Warning") =
vbYes Then
   
       DoCmd.Close acForm, "frmMainIntro", acSaveYes
       DoCmd.Close acDefault, "db.mdb", acSaveYes
       DoCmd.Quit acQuitSaveNone
       Else
       MsgBox ("Exit Application Action Aborted.")
   End If

End Sub

This is easy to do, but first make a back-up copy of your database in case we screw up.

1. Open the Switchboard form in Design View.
2. Go to the code window for this form.
3. Go down to this area:

Private Function HandleButtonClick(intBtn As Integer)

Then look for this bit of code:

' Exit the application.
    Case conCmdExitApplication
    CloseCurrentDatabase

Change that code to this:

' Exit the application.
    Case conCmdExitApplication
    DoCmd.Quit

4. Compile the code and save the form.

5. Use the Switchboard Manager to create an option on your main
page for exiting (if you have not already). Select the command option
that says "Exit Application." Press that option on the form in normal
view and it should close the database and Access as well.

That should do it.