Access 2003
I have a small table with (among other fields) two check boxes one, if
checked, allows that record to be shown on a form. Once that record
has been used that check box is set to 0 while the other is set to 1
"flagged for deletion".
The line of code --- Set rst = db.OpenRecordset("Select * from
qryItemsForDelete;") I thought became the group of data that the code
following would be affecting. So within the qryItemsForDelete there
are two records flagged for deletion. When I click my command button
to delete the two records I get to delete the first two records in the
underlying table rather than the two that are flagged. Here is the
rest of the code. Any suggestions appreciated.
Please ignore the commented out lines Under construction. Many thanks

Private Sub cmdDelete_Click()
Dim Counter As Integer
Dim rst As DAO.Recordset
Dim db As DAO.Database
Set db = CurrentDb()

Set rst = db.OpenRecordset("Select * from qryItemsForDelete;")
With rst
   Counter = 0
   ' Very important to avoid errors if no records are returned
   If Not (.EOF And .BOF) Then
       'movefirst isn't strictly necessary - but just in case
       '.MoveFirst
       Do Until .EOF
           'do something with record
           Counter = Counter + 1
           DoCmd.RunCommand acCmdSelectRecord
           DoCmd.RunCommand acCmdDeleteRecord
           .MoveNext
       Loop
   End If
   .Close
End With
Set rst = Nothing
Set db = Nothing
'MsgBox ("You are about to DELETE" & " " & Counter & " " & "records"),
vbYesNoCancel
End Sub