The combo you are using to filter the form - is it bound to a field?
Or does it show "Unbound" when you open the form in design view?
You need to use an *unbound* combo to filter the form. Don't try to use the
one combo for both data entry and for filtering.

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Allen Browne - Microsoft MVP. Perth, Western Australia
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> I've created a form with a combox box and a button to search for records
> in a
[quoted text clipped - 17 lines]
> to
> have untrue data in my table again.
lhtan123 - 11 Dec 2007 01:21 GMT
So are you suggesting that I create the combo box list using another table
instead of binding the combox box to a field in the table which is the
recordset for the form ?
In that way, I'll have to update the combo box list seperately from the
table everytime when there's a new value. There's no other convenient way ?
> The combo you are using to filter the form - is it bound to a field?
> Or does it show "Unbound" when you open the form in design view?
[quoted text clipped - 23 lines]
> > to
> > have untrue data in my table again.
lhtan123 - 11 Dec 2007 02:56 GMT
Thank you. It works now. But I'm curious about why that occurs.
> So are you suggesting that I create the combo box list using another table
> instead of binding the combox box to a field in the table which is the
[quoted text clipped - 30 lines]
> > > to
> > > have untrue data in my table again.
Allen Browne - 11 Dec 2007 10:18 GMT
You have it working, so that's good.
The idea was not to bind the combo to a different table, but to leave it
unbound.
If the combo is bound to a field, it makes sense that the combo will change
the value of the field *before* you move away from that record and apply a
filter or jump to another.

Signature
Allen Browne - Microsoft MVP. Perth, Western Australia
Tips for Access users - http://allenbrowne.com/tips.html
Reply to group, rather than allenbrowne at mvps dot org.
> Thank you. It works now. But I'm curious about why that occurs.
>
[quoted text clipped - 43 lines]
>> > > to
>> > > have untrue data in my table again.